Gibheer
6ea4d2c82d
lib/pq is out of maintenance for some time now, so switch to the newer more active library. Looks like it finally stabilized after a long time.
86 lines
2.1 KiB
Go
86 lines
2.1 KiB
Go
package genstack
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// GenStack implements a generational stack.
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//
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// GenStack works as common stack except for the fact that all elements in the
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// older generation are guaranteed to be popped before any element in the newer
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// generation. New elements are always pushed to the current (newest)
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// generation.
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//
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// We could also say that GenStack behaves as a stack in case of a single
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// generation, but it behaves as a queue of individual generation stacks.
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type GenStack[T any] struct {
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// We can represent arbitrary number of generations using 2 stacks. The
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// new stack stores all new pushes and the old stack serves all reads.
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// Old stack can represent multiple generations. If old == new, then all
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// elements pushed in previous (not current) generations have already
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// been popped.
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old *stack[T]
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new *stack[T]
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}
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// NewGenStack creates a new empty GenStack.
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func NewGenStack[T any]() *GenStack[T] {
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s := &stack[T]{}
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return &GenStack[T]{
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old: s,
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new: s,
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}
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}
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func (s *GenStack[T]) Pop() (T, bool) {
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// Pushes always append to the new stack, so if the old once becomes
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// empty, it will remail empty forever.
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if s.old.len() == 0 && s.old != s.new {
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s.old = s.new
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}
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if s.old.len() == 0 {
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var zero T
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return zero, false
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}
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return s.old.pop(), true
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}
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// Push pushes a new element at the top of the stack.
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func (s *GenStack[T]) Push(v T) { s.new.push(v) }
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// NextGen starts a new stack generation.
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func (s *GenStack[T]) NextGen() {
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if s.old == s.new {
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s.new = &stack[T]{}
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return
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}
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// We need to pop from the old stack to the top of the new stack. Let's
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// have an example:
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//
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// Old: <bottom> 4 3 2 1
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// New: <bottom> 8 7 6 5
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// PopOrder: 1 2 3 4 5 6 7 8
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//
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//
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// To preserve pop order, we have to take all elements from the old
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// stack and push them to the top of new stack:
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//
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// New: 8 7 6 5 4 3 2 1
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//
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s.new.push(s.old.takeAll()...)
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// We have the old stack allocated and empty, so why not to reuse it as
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// new new stack.
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s.old, s.new = s.new, s.old
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}
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// Len returns number of elements in the stack.
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func (s *GenStack[T]) Len() int {
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l := s.old.len()
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if s.old != s.new {
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l += s.new.len()
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}
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return l
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}
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